The length of the conveyor belt refers to the length of the conveyor belt when it is flattened.

The manufacturer gives the label at the time of production, but when the label is unclear

How to calculate when there is no labeling? Based on years of practical experience

Summarize a more accurate and practical than the usual calculation method

The empirical formula of sex is now introduced as follows.

1 Introduction of common formulas and empirical formulas

Common formula L=l/2(2.nRo+2.hR.)N

Empirical formula L = (2 + (3N) N.n

Where the length of the conveyor belt, m;

Ro roll the radius of the roll core of the conveyor belt, m;

RTI- conveyor belt maximum radius, m;

Conveyor belt thickness, m;

The number of turns taken by the N conveyor belt.

2 The origin of the empirical formula

The shape of the conveyor belt when it is taken up is a spiral, as shown in Figure 1.

Figure 1 Side view of the roll conveyor belt

Because the thickness of the conveyor belt is relatively thin, generally at 0.010~

Between 0.030m, we might as well turn each spiral on Figure 1.

Look at the round lines formed one after another, as shown in Figure 2.

Figure 2 Side view of the roll conveyor belt

Calculate the length of each belt and then add up

Is the length of the conveyor belt, but because the conveyor has a certain thickness

Degree, when calculating the length of the belt conveyor, we take the thickness of the belt

The length of the circumference of the heart line is taken as the length of the belt conveyor, ie:

First lap length: LI=2 (Ro+6/2).丌=2(Ro+6一a/2)sI

Second lap length: = 2 (Ro + 26 a a / 2) si

Length of the third lap: = 2 (Ro + 36 a a / 2) si

Length of the Nth circle: = 2 (Ro + N6 - a / 2) si

It

The length of the volume is: L=LI+ + +? ? + = L=

】 1

It It

Σ 2 (Ro+i6-2).丌 = 2s~NIL +2.丌6Σi one. nN (3=

2s~NR, +2sI~(N+1)×N/2-JIN6=(2Ro+6N)N

That is, L=(2Ro+(3N)N.n

3 example description

When the roll width of the take-up conveyor belt is 0.20m, the belt thickness is thick.

The degree is 0.022m, a total of 3O coils are taken, and the length of the coil is: L=(2

+(3N)NJ1=(2×0.20+30×O.022)3O.丌=99.85m

The actual length of the conveyor belt is: =99.50m

The relative error between the calculated length and the actual length is:

(L-L real) / L real × 100% = (99.85 - 99.5O) /